This method that the facets with the shortest ionization energies would be in the bottom left-hand edge of the regular table. The readjust in ionization energies is also bigger going under the periodic table (by adjust within a group) 보다 going throughout the regular table (by readjust within a period).

You are watching: Arrange the elements in order of decreasing ionization energy.

So let"s start from the bottom of the periodic table:#Pb# is the aspect that is in the lowest period at 6 (and lowest team at 14) in the periodic table; it"s the the smallest ionization energy.

The period above (5) has two the the elements: Sn and also Te. Well, since ionization energy increases throughout a period, Sn will have actually a smaller sized ionization power than Te.#Pb, Sn, Te#

Now, let"s go to the 3rd period, where #S# and also #Cl# are. Due to the fact that #S# is before #Cl,# #S# has actually a reduced ionization power than #Cl#.#Pb, Sn, Te, S, Cl#

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Ernest Z.
Nov 15, 2016

The bespeak is #"Sn .


You have actually learned the ionization power increases from peak to bottom and from left to appropriate in the regular Table.

You more than likely saw a diagram something favor this.


Here"s the section of the regular Table that includes the elements in this question.

(Adapted from ZON PENA)

You would normally predict the order to be


This is almost correct, yet the correct order is #"Sn , as presented in the image below.

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Why is this so?

The electron construction of #"Sn"# is #" 5s"^2 "4d"^10 "5p"^2#.

The electron construction of #"Pb"# is #" 6s"^2 "4f"^14 "5d"^10 "6p"^2#.

The #"4f"# electrons in #"Pb"# are bad at shielding the outermost electrons.

Thus the external electrons suffer a greater efficient nuclear charge, and also it is more challenging to remove them.

Hence #"Pb"# has a greater ionization than #"Sn"#, and also the exactly order is #"Sn .

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I hope that your instructor told you about this phenomenon prior to asking girlfriend to make a prediction.

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