I have actually tried to recognize what the oxidation state for Mn in $\ceMnO4^-$ is. So much i have understood that O have the oxidation state of -2 so since there is 4 O the number transforms to -8. What wake up to the minus at O? and also what is the oxidation state because that Mn?


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The amount of the oxidation states of all of the atoms demands to same the complete charge on the ion.

You are watching: Charge of mn in mno4-

For example, because that $\ceNH4+$, if every hydrogen atom has actually an oxidation state that +1, and the overall charge is +1, climate we can solve for the oxidation state the nitrogen:

$$\beginaligned 4(+1) + OS_\ceN &= +1\\OS_\ceN &= +1 -4(+1) \\OS_\ceN &= -3\endaligned$$

Similarly, we deserve to do $\ceSO4^2-$. If every oxygen atom has an oxidation state the -2, and the all at once charge is -2, we have the right to solve for the oxidation state of sulfur:

$$\beginaligned 4(-2) + OS_\ceS &= -2\\OS_\ceS &= -2 -4(-2) \\OS_\ceS &= +6\endaligned$$


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answered jan 6 "19 at 12:28
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Ben NorrisBen Norris
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Seeing as Oxygen has actually an oxidation state the -2 and also you have actually 4 Oxygen atoms, the complete charge added by Oxygen = -8. Since the total charge of this link = -1, then in this case Mn = +7+7 - 8 = -1


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answered january 6 "19 in ~ 13:32
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PeteLDWPeteLDW
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As you said Oxygen has actually the oxidation state of -2 so if we include up all the oxygens they have actually a -8 oxidation state.

As the oxidation state of the ion is equal to that is charge, the Mn needs to "balance" the -8 to obtain it up to -1. Thus the oxidation state the Mn in Mno4- is +7.


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answered january 6 "19 in ~ 13:33
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LR01LR01
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