I have actually tried to recognize what the oxidation state for Mn in $\ceMnO4^-$ is. So much i have understood that O have the oxidation state of -2 so since there is 4 O the number transforms to -8. What wake up to the minus at O? and also what is the oxidation state because that Mn?

The amount of the oxidation states of all of the atoms demands to same the complete charge on the ion.

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For example, because that $\ceNH4+$, if every hydrogen atom has actually an oxidation state that +1, and the overall charge is +1, climate we can solve for the oxidation state the nitrogen:

\beginaligned 4(+1) + OS_\ceN &= +1\\OS_\ceN &= +1 -4(+1) \\OS_\ceN &= -3\endaligned

Similarly, we deserve to do $\ceSO4^2-$. If every oxygen atom has an oxidation state the -2, and the all at once charge is -2, we have the right to solve for the oxidation state of sulfur:

\beginaligned 4(-2) + OS_\ceS &= -2\\OS_\ceS &= -2 -4(-2) \\OS_\ceS &= +6\endaligned

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answered jan 6 "19 at 12:28

Ben NorrisBen Norris
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Seeing as Oxygen has actually an oxidation state the -2 and also you have actually 4 Oxygen atoms, the complete charge added by Oxygen = -8. Since the total charge of this link = -1, then in this case Mn = +7+7 - 8 = -1

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answered january 6 "19 in ~ 13:32

PeteLDWPeteLDW
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As you said Oxygen has actually the oxidation state of -2 so if we include up all the oxygens they have actually a -8 oxidation state.

As the oxidation state of the ion is equal to that is charge, the Mn needs to "balance" the -8 to obtain it up to -1. Thus the oxidation state the Mn in Mno4- is +7.

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answered january 6 "19 in ~ 13:33

LR01LR01
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