For CuI. We can see that the metal in the ionic compound is Cu (copper), which is a transition metal. This means it has many possible charges.

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The absence of a subscript signifies that copper has acharge of +1. This means the cation isCu+, which is namedcopper (I). On the other hand, the anion in the formula isI–which corresponds toiodine. However, since I– is an anion, we add the suffix–ide, making itiodide.

This means the name of CuI is copper (I) iodide.

For Fe2O3. We can see that the metal in the ionic compound is Fe (iron), which is a transition metal. This means it has many possible charges.

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Problem Details

Give the systematic names of these compounds. Spelling counts!

(a) CuI(s)

(b) Fe2O3(s)

(c) CoF2(s)

(d) FeO(s)


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