For CuI. We can see that the metal in the ionic compound is Cu (copper), which is a transition metal. This method it has many possible charges.

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The lack of a subscript signifies the copper has actually acharge the +1. This method the cation isCu+, which is namedcopper (I). On the various other hand, the anion in the formula isI–which corresponds toiodine. However, due to the fact that I– is one anion, we add the suffix–ide, do itiodide.

This means the surname of CuI is copper (I) iodide.

For Fe2O3. We have the right to see the the metal in the ionic compound is Fe (iron), which is a change metal. This means it has actually many feasible charges.


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Problem Details

Give the organized names of these compounds. Assignment counts!

(a) CuI(s)

(b) Fe2O3(s)

(c) CoF2(s)

(d) FeO(s)

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