## Background

**This is not the conventional explanation of what holds a nucleus together. The conventional explanation is merely a naming of whatholds nuclei together; i.e., the nuclear strong force. This naming has no more empirical content than if physicistssaid something holds a nucleus together. The physicists at the time needed an explanation for how a nucleus composedof positively charged protons could stably hold together. They hypothesized a force which at shorter distances between protonsis more attractive than the electrostatic force is repulsive, but at longer distances is weaker. The only evidence for this hypotheticalnuclear strong force is that there is a multitude of stable nuclei containing multiple protons. According to the theory nuclear stabilitywas aided by the neutrons of a nucleus being attracted to each other as well as to the protons. So the conventional theory is merelyan explanation of how a nucleus containing multiple positive charges can be stable.But even if a theory explains empirical facts that does not mean that it is necessarily true. It only means the theory mightbe physically true. There might be an alternate true explanation of those empirical facts. And if a theory predicts somethings whichdo not occur then even if it explains other things it cannot be physically correct. According to the strong force theory of nuclear structure there should be no limit on the number of neutrons in stable nuclides.There should be ones composed entirely of neutrons. There should even be ones composed entirely of a few protons.These things do not occur physically. In fact there has to be a proper proportion between the numbers of neutrons and protons.In heavier nuclides there are fifty percent more neutrons than protons. Thus there are serious flaws with the conventional theoryof nuclear structure; i.e., the nuclear strong force.When the conventional theory of nuclear structure was formulated physicists thought that they could not bewrong, but, as will be be shown below, they were wrong, because their concept of nuclear strong force conflates two disparate phenomena:spin pairing, attractive but exclusive, and non-exclusive interaction of nucleons in which like-nucleons repel each other and unlike attract. The proof of this assertion is given below. This is an abbreviated version of an alternative of what holds a nucleus together. The full version is at Nucleus.**

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It should be noted that there is a greatdifference among the frequencies of the extra spin pairs. There are 2919 with an alpha module and only 10 without. There are 2668 nuclides with extra neutron-neutron spin pairs, but only 164 out of the 2929nuclides which have one or more extra proton-proton spin pairs. There are 1466 with an extra neutron-proton spin pair.

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## Nuclear Forces

There are three types of forces involved:Forces associated with the formation of spin pairs of the three types, neutron-neutron, proton-proton andneutron-proton. These are effectively forces of attraction. The forces associated with these spin pair formations are exclusive, in the sense that a neutron can pair with one other neutron and with a proton, and no more. It is likewise for a proton.It should be noted that neutron-neutron and proton-proton can only exist within a nucleus; i.e., in conjunction with other spin pairs. A force involving the interaction of nucleons usually called the nuclear strong force which is distance-dependent and drops off faster thaninverse distance-squared. The name strong force is inappropriate because it is not all that strong at relevant distances compared with the forces involved in spin pair formation. A more appropriate name would be nucleonic force, the force between nucleons. For the flaws in the conventional concept of the nuclear strong force see Nuclear Strong Force.Under this force like nucleons are repelled from each other and unlike ones attracted. This astounding proposition will be proved later.The electrostatic (Coulomb) repulsion between protons, which is inversely proportional to distance squared. This force only affects interactions between protons. Neutrons have no net electrostatic charge but dohave a radial distribution of electrostatic charge involving an inner positive charge and a negative outer charge. In principle gravity is also involved but the magnitude of the gravity forces is so small in comparison to the other forces that it can be ignored. As will be shown, the spin paring is exclusive. The nucleonic force is not exclusive but in the interaction between two nucleons the energy associated with theformation of a spin pair is two orders of magnitude larger than that involved in their interaction through the nucleonic force,roughly 13 million electron volts (MeV) compared to 1/3 MeV.However, in a nucleus having many nucleons the magnitude of the energy of the many small energy interactions might possibly exceed thoseof the few spin pair formations. But because the interaction force between like nucleons is repulsion there would have to bea proper proportion between the numbers of neutrons and protons for the net interaction to be an attraction or involve a significant reductionin the repulsion between like nucleons.For heavier nuclei that requires there to be 50 percent more neutrons than protons. That 150 percentratio will be explained later.## Mass Deficits and Binding Energies

The mass of a nucleus made up of many neutrons and protons is less than the masses of its constituent nucleons.This mass deficit when expressed in energy units through the Einstein formula E=mc² is called the bindingenergy of the nucleus. Binding energy is described as the energy required to break a nucleus apart into its constituent nucleons. The total binding energy of a nucleus also includes the loss in potential energyinvolved in its formation as a nucleus. When a nucleus is formed from its constituent nucleons there is a lossof potential energy but a gain in kinetic energy for a net energy loss that is manifested in the form of the emissionof a gamma ray. Unfortunately the total binding energies are not known for the various nuclides except for the deuteron.However there is reason to believe that the lossof potential power is proportional to the mass deficit binding energy. Nevertheless the analysis of the mass deficitbinding energies reveal a great deal about the structure of nuclei. Much of this comes from an examination of incremental binding energies.## Incremental Binding Energies

If n and p are the numbers of neutrons and protons, respectively, in a nucleus and BE(n, p) is theirbinding energy then the incremental binding energies with respect to the number of neutrons and the numbers of protons are given by:IBEn(n, p) = ΔNBE(n, p) = BE(n, p) − BE(n-1, p)and IBEp(n, p) = ΔPBE(n, p) = BE(n, p) − BE(n, p-1)As asserted above the incremental binding energies of nuclides reveal important informationabout the structure of nuclei. Here are some of the characteristics of nuclei revealed by incremental binding energies:The effects of neutron-neutron spin pair formation on binding energyThe sawtooth pattern is a result of the enhancement of incremental binding energy due to the formation of neutron-neutron spin pairs. The regularity of the sawtooth pattern demonstrates thatone and only one neutron-neutron spin pair is formed when a neutron is added to a nuclide.The above graphs are just illustrations of the effect but the same pattern prevails throughoutthe dataset of nearly three thousand nuclides. The same effects occur for proton-proton spin pair formation on binding energyThe pattern of spin pairing described above prevails throughout the more than 2800 cases of theincremental binding energies of protons in addition to the more than 2750 cases of theincremental binding energies of neutrons.. The effect of neutron-proton spin pairs is revealed by a sharp drop in incremental binding energy after the point where the numbers of neutrons and protons are equal. Here is the graph for the case of the isotopes of Krypton (proton number 36).As shown above, there is a sharp drop in incremental binding energy when the number of neutrons exceeds the proton number of 36. This illustratesthat when a neutron is added there is a neutron-proton spin pair formed as long as there is an unpairedproton available and none after that. This illustrates the exclusivity of neutron-proton spin pairformation. It also shows that a neutron-proton spin pair is formed at the same time that a neutron-neutronspin pair is formed.The case of an odd number of protons is of interest. Here is the graph for the isotopes of Rubidium (proton number 37).The addition of the 38th neutron brings the effect of the formation of a neutron-neutron pair but a neutron-proton pair is not formed, as was thecase up to and including the 37th neutron. The effects almost but not quite cancel each other out. It is notable that the bindingenergies involved in the formation of the two types of nucleonic pairs are almost exactly the same, but the binding energy for theneutron-neutron spin pair is slightly larger than the one for a neutron-proton spin pair.This same pattern is seen in the case for the isotopes of Bromine.Thus the pattern of spin pairing described above prevails throughout the more than 2800 cases of theincremental binding energies of protons and the more than 2750 cases of theincremental binding energies of neutrons. There are no exceptions.The components of the incremental binding energy of neutrons can be approximated as follows. For an even proton numberlook at the values of IBEn at and near n=p. Project forward the values of IBEn from n=p-3 and n=p-1 to get a value of ICEn for n=p; i.e.,IBEn(p-1, p) + ½(IBEn(p-1, p) − IBEn(p-3, p) )Likewise the values for IBEn can be projected back fromn=p+1 and n=p+3 to get a value of IBEn for n=p without the effect of either an nn spinpairing or an np spin pairing. This procedure is shown below for the isotopes of Neon (10).When this procedure is carried out numerically the results indicate that 42.7 percent of the incremental binding energy at n=p=10are due to the nn spin pairing, 17.1 percent is due the np spin pair and the other 40.0 is due to the net interactive binding energy.This domination of IBEn by spin pairing can only occur for small nuclides. For iron (p=26) the figures are 16.9 percent for the nn spin pairing, 12.8 percent for np spin pairing, and 70.3 percent due to the net effect of the interactive bindingenergy of the nucleons. It is not just that effects of the spin pairings goes down for the heavier nuclei; it is that those of the interactions goes up. For more onthe components of IBEn see Components of IBEn.## The Interactions of Nucleons through the Nucleonic Force

The most important result of the analysis of incremental binding energy is that like nucleonsrepel each other and unlike attract. Since nucleons in nuclei form spin pairs whenever possible it is expeditious to work with the numbers of neutron-neutron spin pairs and proton-proton spin pairs instead of the numbersneutrons and protons per se. This avoids the complication of the sawtooth pattern. It is found that the increments in the incremental binding energies are related to the interactions of the nucleons. There are theorems (second difference theorem andcross difference theorem) that relate thesecond differences in binding energy to the interaction binding energy of the last two nucleons addedto the nuclide. That binding energy corresponds to the slope of the relationship shown below. Thus if the incremental binding energy of neutronsincreases as the number of protons in the nuclide increases then that is evidence that a neutronand a proton are attracted to each other through the nucleonic force.If the incremental binding energy of neutronsdecreases as the number of neutrons in the nuclide increases then it is evidence that the interaction of a neutronand another neutron is due to repulsion. That is to say, neutrons are repelled by each other. The above two graphs are just illustrations but exhaustive displays are available at neutrons,protons and neutron-protonpairs that like nucleons are repelled from each other and unlike attracted.The theoretical analysis for the proposition is given in Interactions.## Nucleonic Charge

The character of the interaction of two nucleons can be represented by their possessing a nucleonic charge.If the nucleonic charges of two particles are Ω1 and Ω2 then their interaction isproportional to the product Ω1Ω2. Thus if the charges are of the same signthen they repel each other. If their charges are of opposite sign then they are attracted to each other.The electrostatic repulsion between protons simply adds to the effective charge of protons.The amount of the addition depends upon the distance separating the protons. There is no qualitative change in the characteristics of a nucleus due to this force.## Alpha Modules of Neutrons and Protons

The data on incremental binding energies establishes that whenever possible nucleons form spin pairs. Having established this principle it then follows that nucleons in nuclei form chains of nucleons linked together by spin pairing.Let N stand for a neutron and P for a proton. These chains involve sequences of the sort-N-P-P-N- or equivalently -P-N-N-P-. The simplest chain of this sort is the alpha particlein which the two ends link together. These sequences of two neutrons and two protonscan be called alpha modules. They combine to form rings. A schematic of sucha ring is shown below with the red dots representing protons and the black ones neutrons. The lines between the dots represent spin pair bonds.It is to be emphasized that the above depiction is only a schematic. The actual spatial arrangementis quite different. For illustration consider the corresponding schematic for an alpha particleand its spatial arrangement. The depiction of an alpha particle in the style of the above would bethe figure shown on the left below, whereas a more proper representation would bethe tetrahedral arrangement shown on the right.Here is an even better visual depiction of an alpha particle.As previously noted, since nucleons in nuclei form spin pairs whenever possible it is expeditious to work with the numbers of neutron-neutron spin pairs and proton-proton spin pairs instead of the numbersneutrons and protons per se. This avoids the complication of the sawtooth pattern. The graph below demonstrates the existence of nucleonshells.The sharp drop off in the incremental binding energy of neutrons after 41 neutron pairs indicates that a shell was filled and the 42nd neutron pair had to go into a higher shell.Maria Goeppert Mayer and Hans Jensen established a set of numbers of nucleons correspondingto filled shells of (2, 8, 20, 28, 50, 82, 126) nucleons. Those values were based on the relative numbers of stable isotopes. The physicist, Eugene Wigner, dubbed them magic numbers and the name stuck.For more on this topic see Magic Numbers. In the above graph the sharp drop off in incremental binding energy after 41 neutron pairs corresponds to 82 neutrons, a magic numberAnalysis in terms of incremental binding energies reveal that 6 and 14 are also magic numbers. If 8 and 20 are consideredthe values for filled subshells then a simple algorithm explains the sequence (2, 6, 14, 28, 50, 82, 126).First consider the explanation of the magic numbers for electron shells of (2, 8, 18, …).One quantum number can range from −k to +k, where k is an integer quantum number. This means the numberin a subshell is 2k+1, an odd number. If the sequence of odd numbers (1, 3, 5, 7 …) is cumulativelysummed the result is the sequence (1, 4, 9, 16, …), the squared integers. These are doubled becauseof the two spin orientations of an electron to give (2, 8, 18 …).For a derivation of the magic numbers for nucleons take the sequence of integers (0, 1, 2, 3, …) and cumulatively sum them. The result is(0, 1, 3, 6, 10, 15, 21 …). Add one to each member of this sequence to get (1, 2, 4, 7, 11, 16, 22, …).Double these to get (2, 4, 8, 14, 22, 32, 44 …) and then take their cumulative sums. The result is(2, 6, 14, 28, 50, 82, 126), the nuclear magic numbers with 6 and 14 replacing 8 and 20. Note that 8 is 6+2 and 20 is 14+6. There ins evidence that the occupancies of the filled subshells replicate the occupancy numbers for the filled shells. Thus the nucleon shells are filled with rings of alpha modules. The lowest level ring is just an alphaparticle. That is to say, at the center of every nucleus having two or more neutrons and two or more protons there is an alpha particle. Confirmation of this is that some nuclei are unstable and emit one and only one alpha particle.These alpha module rings rotate in four modes. They must rotate as a vortex ring to keep separate the neutrons and protonswhich are attracted to each other. The vortex ring rotates like a wheel about an axis through itscenter and perpendicular to its plane. The vortex ring also rotates like a flipped coin about two different diametersperpendicular to each other.The above animation shows the different modes of rotation occurring sequentially but physicallythey occur simultaneously. (The pattern on the torus ring is just to allow the wheel-like rotation to be observed.) Aage Bohr and Dan Mottleson found that the angular momentum of a nucleus (momentof inertia times the rate of rotation) is quantized to h(I(I+1))½, where h is Planck"s constant divided by 2π and I is a positive integer. Using this result the nuclear rates of rotation are found to be manybillions of times per second. Because of the complexity of the four modes of rotation each nucleonis effectively smeared throughout a spherical shell. So, although the static structure of a nuclear shell is that of a ring, its dynamic structure is that of a spherical shell. The overall structure of a nucleus of filled shells is then of the create At rates of rotation of many billions of times per secondall that can ever be observed concerning the structure of nuclei is their dynamic appearances. This accounts for allthe empirical evidence concerning the shape of nuclei being spherical or near-spherical. For a nucleus consisting of filled shells plus extra neutrons (called halo neutrons) the dynamic appearanceis a spherical core of filled shells with pairs of halo neutrons in orbits about the core.## The Statistical Testing of the Alpha Module Ring Model of Nuclear Structure

For the 2929 nuclides the following variables were computedwhich represent the formation of substructures.The number of alpha modulesThe number of proton-proton spin pairs not included in an alpha moduleThe number of neutron-proton spin pairs not included in an alpha moduleThe number of neutron-neutron spin pairs not included in an alpha module To represent the interactions between nucleons the following variableswere computed.The interactions among the p protons: ½p(p-1) The interactions among the p protons and n neutrons: npThe interactions among the n neutrons: ½n(n-1)The model indicates that nuclear binding energy of nuclides is a linear function of these variables.Here are the regression equation coefficients and their t-ratios (the ratios of the coefficients to their standard deviations).The Results of Regression AnalysisTesting the Alpha Module RingModel of Nuclear StructureVariable | Coefficient(MeV) | t-Ratio |

Number of Alpha Modules | 42.64120 | 923.0 |

Number of Proton-Proton Spin PairsNot in an Alpha Module | 13.84234 | 52.0 |

Number of Neutron-Proton Spin PairsNot in an Alpha Module | 12.77668 | 165.5 |

Number of Neutron-Neutron Spin PairsNot in an Alpha Module | 13.69875 | 65.3 |

Proton-ProtonInteractions | −0.58936 | −113.8 |

Neutron-ProtonInteractions | 0.31831 | 95.8 |

Neutron-NeutronInteractions | −0.21367 | −96.6 |

Constant | −49.37556 | −112.7 |

R² | 0.9998825 |

## Results and Conclusions

The coefficient of determination (R²) for this equation is 0.9998825 and the standard error of the estimate is 5.47 MeV. The average bindingenergy for the nuclides included in the analysis is 1072.6 MeV so the coefficient of variation for the regression equation is 5.47/1072.6=0.0051.Most impressive are the t-ratios. A t-ratio of about 2 is considered statistically significant at the 95 percent level of confidence. The level of confidencefor a t-ratio of 923 is beyond imagining.It is notable that the coefficients for all three of the spin pair formations are roughly equal. They all are larger from what one would expect fromthe binding energies of small nuclides.The regression coefficients for the nucleonic force interactions have some especially interesting implications.Without loss of generality the force between two nucleons with charges of Ω1 and Ω2 can be represented as F = HΩ1Ω2f(s)/s²where H is a constant, s is the separation distance and f(s) could be a constant or a declining function of s, possibly exp(−s/s0). Let the nucleonic force charge of a proton be takenas 1 and that of a neutron as q, where q might be a negative number. The nucleonic force interactions between neutrons is proportional to q²,and those between neutrons and protons would be proportional to q. Thus the ratio of thecoefficient for neutron-neutron interactions to that for neutron-proton interaction would be equal to q. The value of that ratio iscnn/cnp = −0.21367/0.31831 = −0.67127.This is confirmation of the value of −2/3 found in previous studies. Thus the nucleonic force between like nucleons is repulsion and attraction between unlike nucleons. The values involving proton-proton interactions are most likely affected by theinfluence of the electrostatic repulsion between protons. That force would be as ifthe charge of the proton were (1+d) where d is the ratio of the electrostatic force to thenucleonic force. More on this later.## Nuclear Stability

An alpha module thus has a nucleonic charge of +2/3=(1+1-2/3-2/3). Therefore two spherical shells composed of alpha modules would be repelled from each other if the spherical shells are separated from each other. This would be a source of instability. But if the spherical shells are concentric the repulsion is a source of stability.Here is how that works. As noted before without loss of generality the force between two nucleons with charges of Ω1 and Ω2 can be represented as F = HΩ1Ω2f(s)/s² where s is the separation distance between them, H is a constant, q1 and q2are the nucleonic charges and f(s) is a function of distance. For the nucleonic force it is presumed thatf(s) is a positive but declining function of distance. This means that the nucleonic force drops offmore rapidly than the electrostatic force between protons. When one spherical shell is located interior to another of the same charge the equilibrium is wherethe centers of the two shells coincide. If there is a deviation from this arrangement the increased repulsionfrom the areas of spheres which are closer together is greater than the decrease in repulsion fromthe areas which are farther apart. This only occurs for the case in which f(s) is a declining function.If f(s) is constant there is no net force when one sphere is entirely enclosed within the other. For moreon this surpris The regression of the number of neutrons on the number of protons gives the equation n = 1.57054p − 10.83610 The coefficient 1.57054 corresonds to |q|=2/3 and d=0.078.## The Statistical Explanatory Power of the Model

Regression equations for the binding energies of almost three thousand nuclides based upon the modelpresented above have coefficients of determination (R²) ranging from 0.9999 to 0.99995 with all ofthe regression coefficients being of the right sign and relative magnitude. SeeStatistical Performance for the details.## The Statistical Testing of the Conventional strong force model of Nuclear Structure

Let n and p be the numbers of neutrons and protons, respectively, in a nuclide. The number of neutron-neutron interactionsis equal to n(n-1)/2. This will be denoted as nn. Likewise the number of proton-proton interactions is p(p-1)/2 and this will bedenoted as pp. The number of neutron-proton interactions is np.The binding energy due to these interactions is a function of the separation distances of the nucleons. Here no distinction is made for separation distances so the results will be for the average separation distance of the nucleon.## The Conventional Model of Nuclear Structure

The regression equation expressing the attempt to predict the binding energy of a nuclidefrom the numbers of the interactions of its nucleons isBE = cnnnn + cnpnp + cpppp`There is no constant term because if nn=np=pp=0 the BE must be zero.The conventional model of nuclear structure is then expressed ascnn = cnp > 0 0 pp nnAccording to the Conventional Model the coefficient for proton-proton interactions should be less than that for neutron-neutron interaction because of the electrostatic repulsionbetween protons.See more: Which Best Describes The Part Of Africa Above The Equator ? World Geography