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**Volume of this solids are depending upon the area of your bases.Volume of triangle Pyramid V = 1/3 x Area that triangular basic x height(H)V = 1/3( base x height) / 2 x HVolume that Hexagonal PyramidV = 1/3 x Area that hexagon x HV = 6 x (√3 / 4 ) (side)2 x HV = 1/3(AP/ 2) x H ( A = apothem ; ns = perimeter)Volume of Pentagonal PyramidVolume = 1/3 x area of basic x height(H)V = 1/3 (AP/ 2) x H ( A = apothem ; ns = perimeter)**

Some solved examples

**1) If the size of every side that the base of a triangle pyramid is 6 cm and also its height is 10 cm, discover its volume. ( √3 = 1.73)Solution :**

**Area of basic = √3 / 4 x (side)2⇒ Area = √3 / 4 x (6)2⇒ Area = √3 /4 x 36∴ Area = 9 √3 cm2Pyramid volume = 1/3 x area of base x height⇒ Pyramid volume = 1/3 x 9 √3 x 10⇒ Volume = 30 √3⇒ Volume = 30 x 1.73⇒ Volume = 51.9 cm3_____________________________________________________________________2) If the length of every side that a square pyramid is 4 cm and its elevation is 12 cm.Solution :**

**Area of basic = side x side⇒ Area = 4 x 4⇒ Area = 16 cm2Pyramid volume = 1/3 x area of basic x height⇒ Volume = 1/3 x 16 x 12⇒ Volume = 64 cm3_____________________________________________________________________3) discover the volume of a consistent hexagonal pyramid with an apothem length of 6 cm,side 3 cm and height of the pyramid is 21 cm.Solution :**

**apothem = A = 6 cm and side = 3 cm height = H =21 cmPerimeter = 3 x 6 = 18 cmArea of base (hexagon) = AP /2⇒ Area = (6 x 18 )/2⇒ Area = 54 cm2volume that pyramid=1/3 x( Area that base) x H∴ V = 1/3 x 54 x 21∴ Volume = 378 cm3Volume :• Volume Formulas• Volume of irregular Shape• Volume the Cube• Volume of rectangular Prism(Cuboid)• Volume the Cylinder• Cone volume• Sphere"s volume• Hemisphere"s volume• Prism"s volume• Volume of PyramidFrom Pyramid to MensurationFrom Pyramid to house Page**

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