For the first question, we want to look at potential intermolecular pressures that are acting to host the molecule together. The one with the weakest IMF will have the lowest boiling point.

You are watching: Which of the following has the lowest boiling point

CH4 has only dispersion pressures while all the others have dispersion PLUS either dipole-dipole (HCl, H2S, NH3), and/or hydrogen bonding (NH3). So, CH4 will have actually the lowest boiling point.

For the second question, we desire to look because that the molecule that dissociates/ionizes right into the most variety of ions. This will certainly be NaCl(l) because solids don"t do so and H2O(g) only ionizes ever before so slightly.

So, the answer is NaCl(l) is the finest conductor.


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Salo O.

Hello, say thanks to you! Also, because that the 2nd question, might you determine the answer by recognize what pressures the molecule has, even if it is it is dispersion or dipole-dipole or hydrogen bonding and then recognize the finest conductor of electricity?
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J.R. S.


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no really. As far as electrical conductivity, friend are much more interested in intramolecular forces than you space in intermolecular forces, and likewise the number of ions present. Because that example, 1 M CaCl2 is a much better conductor 보다 1 M NaCl since it produces more ions.
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